Kris Bryant, Mike Trout earn 2016 MLB MVP honors

Kris Bryant and Mike Trout announced as 2016 NL and AL MVP winners.

After leading the Chicago Cubs to their first World Series title since 1908, Kris Bryant added an NL MVP award to his trophy case. Mike Trout of the Los Angeles Angels, earned the award in the American League.

Following a season in which he hit 39 home runs and scored a league-leading 121 runs, Bryant won the award in a landslide. According to the Baseball Writers Association of America, the third baseman received all but one first place vote. Washington Nationals second baseman Daniel Murphy received the other first place vote, coming in second place.

Rounding out the top five in the NL were the Dodgers’ Corey Seager, Cubs’ Anthony Rizzo, and Rockies’ Nolen Arenado.

Per the BBWAA, the American League Most Valuable Player vote was much closer. Trout won with 19 out of 30 first place votes. Red Sox outfielder Mookie Betts collected nine, while teammate David Ortiz and Rangers third baseman Adrian Beltre each had one.

Although not receiving any first place votes, Astros second baseman Jose Altuve came in third place. The Blue Jays’ Josh Donaldson and Orioles’ Manny Machado rounded out the top five, respectively.

Each voter selects their top ten players on the ballot; the ranking is done on cumulative points.

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Bryant will take home the hardware in only his second season in the Major Leagues. He finished 11th in the NL MVP vote last year.

For Trout, it will be his second time receiving the honor. He also was the runner-up for the AL MVP in 2012, 2014, and 2015. The 25-year-old slugger joins Barry Bonds as the only players to ever finish in the top two during a five-year stretch.

In an era where baseball has become reliant on sabermetrics, Kris Bryant (7.7) and Mike Trout (10.6) each led their respective leagues in WAR (wins above replacement). WAR is a sabermetric statistic that determines how valuable a player is to his team.