Long Odds On The Oakland Raiders Not Winning A Game

Nov 2, 2014; Seattle, WA, USA; Oakland Raiders quarterback Derek Carr (4) throws a pass against the Seattle Seahawks at CenturyLink Field. Mandatory Credit: Kirby Lee-USA TODAY Sports
Nov 2, 2014; Seattle, WA, USA; Oakland Raiders quarterback Derek Carr (4) throws a pass against the Seattle Seahawks at CenturyLink Field. Mandatory Credit: Kirby Lee-USA TODAY Sports

The Oakland Raiders may be winless with eight games left to play, but Las Vegas says it’s still a longshot they end up 0-16.

More from Las Vegas Raiders

The Oakland Raiders have eight games left to play in a season where they are currently winless. Their schedule hardly gets easier, with six of those games being against teams with winning records. They still have to play the Kansas City Chiefs twice and the Denver Broncos once, not to mention two always-tough NFC West teams in the St. Louis Rams and San Francisco 49ers.

Despite that scheduling reality, according to Pro Football Talk, a Las Vegas sports book still has the 2014 Raiders as a relative longshot to go winless and join the 1976 Buccaneers and 2008 Lions as the only teams to lose every game in the regular season.

Micah Roberts, of The Linemakers of Sporting News, posted that the South Point Hotel and Casino in Vegas have put the Raiders at 10-1 to finish the season without a win. That makes it about a nine percent chance that the Raiders lose the rest of their games to go 0-16.

The ‘no’ side of that bet is -1800, which works out to be a 94.7 percent chance that the Raiders do not finish worse than 0-15-1. Currently, most of the betting on this prop is on the Raiders going winless. At the time of the story, 53 of 54 bets were on this outcome. One of these bettors took a $1500 shot at the Raiders losing out. The bet for the Raiders doing no worse than 0-15-1? $18, which would yield a $1 profit.

Not a lot of confidence in this Raiders team from the Vegas end.

More from FanSided